k^2=225k

Solution for k^2=225k equation:

k^2=225k

We move all terms to the left:

k^2-(225k)=0

a = 1; b = -225; c = 0;
Δ = b2-4ac
Δ = -2252-4·1·0
Δ = 50625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50625}=225$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-225}{2*1}=\frac{0}{2}
=0
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+225}{2*1}=\frac{450}{2}
=225
$